What is the equation of the line perpendicular to #y=6/7x # that passes through # (1,-3) #?

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Answer 1 · 2016-05-24T04:50:07

#y=-7/6x-11/6#

Given -

#y=6/7x#
Slope of the given line #m_1=6/7#

Two lines are perpendicular if -

#m_1 xx m_2=-1#

#m_2# is the slope of the required line.

#6/7 xx m_2=-1#
#m_2=-1 xx 7/6=-7/6#

Equation of the perpendicular line -

#y=mx+c#
#-3=-7/6(1)+c#
#c-7/6=-3#
#c=-3 +7/6=(-18+7)/6=-11/6#

#y=-7/6x-11/6#