How do you write $10x(9x^2 + 6x + 7)$ in standard form?

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Answer 1 · 2016-05-25T09:52:27

$=>y=90x^3+60x^2+70x$

Multiply everything inside the rackets by $10x$

$=>y=90x^3+60x^2+70x$

If it is required that the constant term is included then you have:

$=>y=90x^3+60x^2+70x+0$

How do you write 10x(9x^2 + 6x + 7) 10x(9x^2 + 6x + 7) in standard form?