How do you normalize (18i -30j -12k) (18i−30j−12k)?

1 Answer
David G.
May 26, 2016

Normalising a vector involves dividing each of its elements by its length, to yield a new vector of length 1 unit in the same direction as the original vector. In this case, the length of the vector is 3737 units so the normalised vector is (18/37i-30/37j-12/37k)(1837i−3037j−1237k).

Explanation:

Length of the vector:

l=sqrt(18^2+(-30)^2+(-12)^2)=sqrt(324+900+144)=sqrt(1368)~~37l=√182+(−30)2+(−12)2=√324+900+144=√1368≈37

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