How do you evaluate #cos 892° #? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer A. S. Adikesavan May 29, 2016 #- cos 8^o=-0.9903#, nearly. Explanation: Use cos (odd multiple of 180-a)#=-cos a#. Here this angle is in the second quadrant. #cos 892^o# #=cos (900-8)^o# #= cos (5X180-8)^o# #=-cos 8^o=-0.9903,# nearly. Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 2050 views around the world You can reuse this answer Creative Commons License