How do you differentiate #f(x)=(2x)/(x^2+1)#?

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Answer 1 · 2016-05-29T10:17:38

#d f(x)=(2 *d x)/(x^2+1)#

#d f(x)=(2x)/(x^2+1)*d x#

#d f(x)=(2(x^2+1)+2x*2x)/(x^2+1)^2 *d x#

#d f(x)=(2(x^2+1)+4x^2)/(x^2+1)^2 * d x#

#d f(x)=(2x^2+2+4x^2)/(x^2 +1)^2 *d x#

#d f(x)=(6x^2+2)/(x^2+1)^2 *d x#

#d f(x)=(2cancel((x^2+1)))/cancel((x^2+1))^2* d x#

#d f(x)=(2 *d x)/(x^2+1)#