#H_0# km/sec/mega parsec
#=H_0 X 10^(-6)# km/sec/parsec
#=(H_0 X 10^(-6)/206265)=4.85 x 10^(-12)H_0# km/sec/AU
#=(((H_0 X 10^(-6)/206265))/149597871)= 3.24 X 10^(-20)H_0# km/sec/km
#=(((H_0 X 10^(-6)/206265))/149597871)(365.25 X 24 X 3600)#
#=1.02 X 10^(-12)H_0# km/year/km
In this second edition, i convert #H_0 to age of our universe, in the
Hubble way.
The age of our universe is #1/H_0# years, where #H_0# is obtained
in u/year/u, with u some unit of distance, at your choice.
This invariant factor to be applied to the standard #H_0= 71#
km/sec/parsec is #1.02 X 10^(-12)#
Now, #1/(converted H_0)#
#=1/(71 X 1.02 X 10^(-12)) = 1.38 X 10^10# years.
#=13.8# billion years.
