How do you write #(3x^2 + 7) – (x^2 – 6x + 4) # in standard form? Algebra Polynomials and Factoring Addition and Subtraction of Polynomials 1 Answer Tony B May 30, 2016 #2x^2+6x+3# Explanation: The minus sign in front of #-(x^2-6x+4)# means that you multiply everything inside the brackets by #(-1)# So #color(brown)(-(x^2-6x+4)" "color(blue)(->" "-x^2+6x-4)# #color(green)("Putting it all together")# #color(brown)((3x^2+7)-(x^2-6x+4)" "color(blue)(->" "3x^2+7-x^2+6x-4)# #color(green)("Grouping like terms")# #(3x^2-x^2)+(+6x)+(7-4)" "->" "2x^2+6x+3# Answer link Related questions How do you add two polynomials? How do you subtract two polynomials? How do you add and simplify #3x^2-4x+7# and #2x^3-4x^2-6x+5#? How do you subtract #5b^2-2a^2# from #4a^2-8ab-9b^2#? How do you simplify #(6.9a^2-2.3b^2+2ab)+(3.1a-2.5b^2+b)#? How do you simplify #(-t+15t^2)-(5t^2+2t-9)#? How do you subtract #(-5m^2-m)-(3m^2+4m-5)#? How do you add two polynomials if they don't have like terms? How do you simplify #(3a+4b)-(-6a-3b)#? How do you subtract #(x^2-8x+7)-(6x^2+7x-3)#? See all questions in Addition and Subtraction of Polynomials Impact of this question 1471 views around the world You can reuse this answer Creative Commons License