How do you solve for y in #5xy + 2x = 3#?

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Answer 1 · 2016-05-30T14:31:57

#y=3/(5x)-2/5#

From the given equation

#5xy+2x=3#

#5xy=3-2x#

#(cancel(5x)y)/cancel(5x)=(3-2x)/(5x)#

#y=(3-2x)/(5x)#

#y=3/(5x)-2/5#

God bless....I hope the explanation is useful.