Question

What volume would 5 moles of Helium occupy at 278°C and 765 mmHg?

Answer 1

Approx. `220*L`.

Explanation:

We use the ideal gas equation with the appropriate constant. We know that `1*atm` `-=` `760*mm*Hg` (or more correctly, `1*atm` will support a column of mercury `760*mm` high).

`V=(nRT)/P` `=` `(5*molxx0.0821*L*atm*K^-1*mol^-1xx546*K)xx((765*mm*Hg)/(760*mm*Hg*atm^-1))^-1`

`=` `??L`