How do you solve e^x + 3 = 6?

1 Answer
May 31, 2016

color(green)(x=ln(3) ~~1.099" to 3 decimal places")

Explanation:

color(blue)("Introduction of concepts"

Example of principle: Try this on your calculator

Using log to base 10 enter log(10) and you get the answer of 1.

Log to base e is called 'natural' logs and is written as ln(x) for any value x

color(brown)("Consequently "ln(e)=1) Try that on your calculator

[ you may have to enter ln(e^1) ]

Another trick is that log(x^2) -> 2log(x) => ln(x^2)=2ln(x)

Combining these two ideas:

ln(e^2)" "=" "2ln(e)" "=" "2xx1=2

color(brown)("So "ln(e^x)" "=" "xln(e)" "=" "x xx1" " =" " x)

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color(blue)("Solving the question")

Given:" "e^x+3=6

Subtract 3 from both sides

" "e^x=6-3

" "e^x=3

Take logs of both sides

" "ln(e^x)=ln(3)

" "xln(e)=ln(3)

But ln(e)=1 giving

color(green)(x=ln(3) ~~1.099" to 3 decimal places")