Question

How do you solve `4x^2 - 4x + 1 = 36`?

Answer 1

`x={-5/2,7/2}`

Explanation:

`4x^2-4x+1=36`

`4x^2-4x+1-36=0`

`4x^2-4x-35=0`

`(2x-7)(2x+5)=0`

`(2x-7)=0" "rarr" "2x=7" "x=7/2`

`(2x+5)==" "rarr" "2x=-5" "x=-5/2`