Which of the ordered pairs is a solution for the equation 4x - 2y = 8 (0,4), (-2,0) (-2,-4)(0,-4)?

1 Answer
Jun 2, 2016

#(0, 4)#

Explanation:

You have to check if the ordered pair is true for the given equation
So given #4x -2y =8#
Firstly re-arrange this to #2y = 4x - 8#
which can then be divided by 2 to give
#y = 2x - 4#
Now check each ordered pair
for #(0, 4)# substitute # x = 4# into the Rihgt hand Side (RHS) to get #(2xx4) - 4 = 8 - 4 = 4#
So for this pair #y = 4# and the pair satisfies the equation
Now check #(-2, 0)# in the same way
When #x = -2#
RHS = #(4xx -2) - 4 = -12# which does not equal LHS = 0
Now check #(-2 , -4)# the x valie is the same as before, so this does not work either
Lastly check #(0, -4)# but this does not equal the RHS when #x = 0# either
So the only solution is #(0, 4)#