Question

How do you write the equation of the circle with center (2, -1) and r = 8?

Answer 1

`(x-2)^2+(y+1)^2=64`

Explanation:

`C=(a,b)" the center coordinates of circle"`

`a=2" ," b=-1" ,"r=8`

`r="radius of circle"`

`(x-a)^2+(y-b)^2=r^2" circle equation"`

`(x-2)^2+(y+1)^2=8^2`

`(x-2)^2+(y+1)^2=64`