Question

How do you differentiate `f(x)=sin(e^(3x^3-x))` using the chain rule?

Answer 1

`d/(d x) f(x)=e^(3x^3-x) *(9x^2-1)*cos(e^(3x^3-x))*l n (e)`

Explanation:

`f(x)=sin(e^(3x^3-x))`

`d/(d x) f(x)=e^(3x^3-x) *(9x^2-1)*cos(e^(3x^3-x))*l n (e)`