How do you solve #(x-3) /4 + x/2 =3#?
2 Answers
Explanation:
First, we remove the fractions by multiplying the equation by the LCM of
LCM of
Multiply the equation by
This means, the expression on the left side of the = sign will be multiplied by
Next, add
Finally, divide both sides by
You can check your answer by putting back the value
Solving the left side:
x = 5
Explanation:
To eliminate the fractions in this equation
#color(blue)"multiply all terms on both sides"# by the L.C.M. (lowest common multiple) of 2 and 4 which is 4.
#rArr[cancel(4)^1 xx(x-3)/cancel(4)^1]+[cancel(4)^2xxx/cancel(2)^1]=4xx3# The equation now simplifies to
x - 3 + 2x = 12
hence : 3x - 3 =12
and 3x = 15
divide both sides by 3
#(cancel(3)^1 x)/cancel(3)^1 =15/3#
#rArrx=5" is the solution"#