A charge of #54 C# passes through a circuit every #6 s#. If the circuit can generate #162 W# of power, what is the circuit's resistance?

2 Answers
Jun 3, 2016

#R=2" "Omega#

Explanation:

#I=(Delta Q)/(Delta t)" Current of circuit"#

#Delta Q=54C" ; "Delta t=6 s#

#I=54/6=9 " "A#

#P:"Power"#

#R:"Resistance"#

#P=I^2*R#

#162=9^2*R#

#R=162/81#

#R=2" "Omega#

Jun 3, 2016

I found #2Omega#

Explanation:

You know that current #I# is the charge passing a section of conductor each second.
In your case you have:
#I=Q/t=54/6=9A#
Power is the rate of transformation (work) energy with time:
#P=E/t=V*I#
Using Ohm's Law we get:
#P=I^2R#
rearranging:
#R=P/I^2=162/(9^2)=2Omega#