Question

How do you find the vertical, horizontal or slant asymptotes for `f(x)=(x-4)^2/(x^2-4)`?

Answer 1

Vertical asymptotes x= 2, x= -2

Horizontal asymptote y=1

Explanation:

Vertical asymptotes are given by Eq `x^2-4=0` which gives x=2, x=-2

For slant/horizontal asymptotes write f(x) = `1 +(20-8x)/(x^2-4)`

Asymptote given by y=1 is a horizontal asymptote. There is no slant asymptote