How do you find the instantaneous rate of change of the function #x^3+x^2 # when x=2?
1 Answer
Jun 4, 2016
16
Explanation:
The
#color(blue)"instantaneous rate of change"# is the value of f'(2).
#f(x)=x^3+x^2rArrf'(x)=3x^2+2x# and
#f'(2)=3(2)^2+2(2)=16" is the instantaneous rate of change"#
