Question

A neon gas in a sign has a volume of 42.5 L at 25 °C and 3.5 kPa. What is the mass of neon?

Answer 1

Approx. `1*g`.

Explanation:

`n=(PV)/(RT)` `=` `(3.5xxkPaxx42.5*L)/(8.314*L*kPa*K^-1* mol^-1xx298*K)`

`=` `6.00xx10^-2*mol`

Thus `"mass neon"` `=` `6.00xx10^-2*molxx20.18*g*mol^-1` `=` `??g`