Question #91a43

1 Answer
Jun 5, 2016

A rounded 5-sd set of solutions is
#x = (4n +0.76528) pi, n=0, +-1, +-2, +-3, ...#.
Of course, #x =0, +-2pi, +-4pi, +-6pi, ..#are also solutions.

Explanation:

Let #y(x)=sin x + 1.5 sin (1.5 x )#

This represents the compounded oscillation of the separate

oscillations for sin x and 1.5 sin (1.5 x ) of periods #2pi and (4pi)/3#,

respectively.

Now, #y(x+4pi)=y(x)#. So, y is periodic with period #4pi#.

I have obtained one approximate solution from

#y(137,753^o) = y(0.76528 pi)=0.000001#, nearly.

This 5-sd solution #in (0, 2pi)# was obtained by using a

convergent root-bracketing (optimized bisection) method.

Correspondingly, the set of genera(.solutions is obtained as

#x = (4n +0.76528) pi, n=0, +-1, +-2, +-3, ...#

Likewise, another such root #in (2pi, 4pi)# could be approximated.

Correspondingly, one more set of general solutions

could be obtained.

Indeed, y becomes 0, for x= #2npi, n=0,+-1,+-2,+-3,..#