How do you solve #3^(x-1)= 27/3^x#?

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Answer 1 · 2016-06-07T07:40:45

We can use the laws of exponents and simplify to get the answer.
Answer : #x = 2#

# 3^(x-1) = 27/ (3^x) #

# 3^(x-1) = 3^3/3^x #

# 3^(x-1) = 3^(3-x) #

As the bases are equal, we can equate the exponents.

# x - 1 = 3 - x #

# x + x = 3 + 1 #

# 2x = 4 #

# x = 2 #