Question

What is the perimeter of a triangle with corners at `(7 ,3 )`, `(1 ,5 )`, and `(2 ,4 )`?

Answer 1

Perimeter is `12.84`.

Explanation:

Let us find the sides of triangle formed by `(7,3)`, `(1,5)` and `(2,4)`. This will be surely distance between pair of points, which is

`a=sqrt((1-7)^2+(5-3)^2)=sqrt(36+4)=sqrt40=6.3246`

`b=sqrt((2-1)^2+(4-5)^2)=sqrt(1+1)=sqrt2=1.4142` and

`c=sqrt((2-7)^2+(4-3)^2)=sqrt(25+1)=sqrt26=5.099`

Hence perimeter is `6.3246+1.4142+5.099=12.8378` or say `12.84`.