How do you factor #9c^2+6c+1 #? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Konstantinos Michailidis Jun 8, 2016 Notice that #9c^2+6c+1=(3c)^2+2*(3c)+1=(3c+1)^2# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 2428 views around the world You can reuse this answer Creative Commons License