Question #4cdbc

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Question #4cdbc

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Answer 1 · 2016-06-12T11:26:19

There are indeed 7 oxygen atoms in this equation.

Explanation:

I edited your question to make it more understandable. Maybe now you can see that there are indeed 7 oxygen atoms?

Lets first see how much of each element is in $2 C O_{2}$ $2CO_2$ :
you should read this as: $2 \cdot (C + O_{2})$ $2*(C + O_2)$
which is similar to: $2 \cdot C + 2 \cdot (O + O)$ $2*C + 2* (O+O)$
so there are $2$ $2$ carbon atoms ( $C$ $C$ ) and $2 \cdot 2 = 4$ $2 * 2 = 4$ oxygen ( $O$ $O$ ) atoms.

Than the elements in the second part $3 H_{2} O$ $3H_2O$ :
this you should read as: $3 \cdot (H_{2} + O)$ $3* (H_2 + O)$
which is similar to: $3 \cdot (H + H) + 3 \cdot O$ $3 * (H + H) + 3 * O$
so there are $6$ $6$ hydrogen ( $H$ $H$ ) atoms and $3$ $3$ oxygen ( $O$ $O$ ) atoms

In total: $4 \cdot O$ $4 * O$ in $2 C O_{2}$ $2CO_2$ and $3 \cdot O$ $3 * O$ in $3 H_{2} O$ $3H_2O$ = $7$ $7$ oxygen atoms

Answer 2 · 2016-06-12T11:28:37

There are seven Oxygen atoms in the reaction.

Explanation:

The numbers in front of the chemical formula indicate how many lots of that compund you have. The numbers apply to each element in the compound.

The example states:
$2 C O_{2} + 3 H_{2} O$ $2CO_2+3H_2O$

If the numbers apply to each element, and there is a small subscript number next to it, then you multiply them together.

For example, $2 C O_{2}$ $2CO_2$ . Here there are 2 carbon atoms, as there is no number, which means that you only have one, and since there are 2 lots of $C O_{2}$ $CO_2$ , then you will have 2 carbon atoms and 4 oxygen atoms.

If we then apply this to the water molecules, we find that there are a total of 2 carbon atoms, 7 oxygen atoms, and 6 hydrogen atoms.

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Question #4cdbc

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