Question

How do you simplify `log_3 3 + log_2 64`?

Answer 1

`log_3(3)+log_2(64)=7`

Explanation:

We use identities `log_aa=1` and `log_a(a^m)=m`

Hence `log_3(3)+log_2(64)`

= `log_3(3)+log_2(2^6)`

= `1+6=7`