How do you add #3 5/8 + 4 3/12#?

2 Answers
Jun 11, 2016

#3 5/8 + 4 3/12 = 7 7/8 #

Explanation:

#3 5/8 + 4 3/12# is short writting of #3+ 5/8 + 4+ 3/12#. Fractional parts can be added easily after reduced to the same denominator.

#5/8+3/12=5/(4 xx 2)+3/(3 xx 4) =(3 xx5)/(3 xx 4 xx 2)+(2 xx 3)/(2 xx3 xx 4) =7/8#

Finally

#3 5/8 + 4 3/12 = 7+7/8 = 7 7/8 #

Jun 14, 2016

In support of solution by Cesareo

#ul("If it is needed")# an in depth explanation about changing fractions so that you can add or subtract.

Explanation:

Detailed explanation on how to deal with converting the whole numbers into fraction form. Also how to convert the fraction such that the fraction's bottom numbers (denominators) are the same.

#color(brown)("Five important facts")#

#color(brown)("Fact 1")#
#" "# Multiply a number by 1 and you do not change its value.

#color(brown)("Fact 2")#
#" "#The value of 1 comes in many forms so you can change the
#" "# way a number looks without changing its inherent value.

#color(brown)("Fact 3")#
#" "# The way that a fraction functions means that it is
#" "#basically of the structure type:

#" "("count of what you are looking at")/("size indicator of what you are looking at")#

#color(brown)("Fact 4")#
#" "#You can not directly subtract or add the count parts of
#" "#fractions unless their size parts are the same.

#color(brown)("Fact 5")#
#" "#Once the size parts of fractions are the same adding or #" "#subtracting the count parts does not change the size part.

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Consider " 3 5/8)#

Write as #3/1+5/8#

To make the size parts (denominators) the same multiply #3/1# by 1 but in the form of #8/8# giving

#(3/1xx8/8)+5/8" "->" "((3xx8)/(1xx8))+5/8#

#=" "24/8+5/8" " =" " (24+5)/8" "=" "color(green)( 29/8)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Consider " 4 3/12)#

Write as #4/1+3/12#

Multiply #4/1# by 1 but in the form of #1=12/12# giving

#(4/1xx12/12)+3/12" "->" "((4xx12)/(1xx12))+3/12#

#=36/12+3/12" "=" "(36+3)/12" "=" "color(green)(39/12)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
From this point you should be able to take over!