How do you convert #xy=5x^2-3x+2y# into a polar equation?

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Answer 1 · 2016-06-15T11:55:38

#r=5rtantheta-3csctheta+2sectheta#

We know that if a point in X-Y
plane has rectangular coordinate #(x,y)# and its polar coordinate is #(r,theta)#,then we have the relation

#x=rcostheta and y =rsintheta#

and # r=sqrt(x^2+y^2)#

Now the given equation is

#xy=5x^2-3x+2y#

#=>rcostheta*rsintheta=5r^2sin^2theta-3rcostheta+2rsintheta#

Deviding both sides by #rsinthetacostheta#

#r=5rtantheta-3csctheta+2sectheta#