How do you solve #3^(x-4)= 27^(x+2)#?

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Answer 1 · 2016-06-16T14:07:02

The answer is #x=-5#

#3^(x-4)=27^(x+2)#

First step is to write #27^(x+2)# as the power of #3#

#3^(x-4)=3^(3(x+2))#

Now you can write this equation as the equation of exponents:

#x-4=3(x+2)#

#x-4=3x+6#

#x-3x=6+4#

#-2x=10#

#x=-5#