How do you solve #12t + 9 = 5t²#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer EZ as pi Jun 17, 2016 #t = 3 or t = -3/5# Explanation: Make the quadratic equal to 0. #5t^2 - 12t -9 = 0# #(5t + 3)(t -3) = 0 " factorise"# #5t + 3 = 0 rArr 5t = -3 rArr t = -3/5# #t- 3 = 0 rArr t =3# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2037 views around the world You can reuse this answer Creative Commons License