Question

How many moles of chlorine gas are contained in a 5.00 L flask at 27°C and .947 atm pressure?

Answer 1

Approx. `0.2*mol`

Explanation:

`n` `=` `(PV)/(RT)`

`=` `(0.947*atmxx5.00*L)/(0.0821*L*atm*K^-1*mol^-1xx300*K)`

If you cancel thru units you get an answer in `"moles"`, as required.