How do you find the exact value of 2 cos pi/3 - 6 tan pi/3? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. Jun 19, 2016 #1 - 6sqrt3# Explanation: Trig table --> #2cos (pi/3) = 2(1/2) = 1# #6tan (pi/3) = 6(sqrt3)# Therefor, #2cos (pi/3) - 6tan (pi/3) = 1 - 6sqrt3# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 2001 views around the world You can reuse this answer Creative Commons License