How do you calculate #Log_5 sqrt542 #? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Tony B Jun 19, 2016 I will let you finish this off Explanation: #log_5sqrt(542)=log_10sqrt(542)/(log_10(5))# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1605 views around the world You can reuse this answer Creative Commons License