How do you solve #2/3 = 2 - (5x-3)/(x-1)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Burglar Jun 19, 2016 #x=5/11#. Explanation: #2/3=2-(5x-3)/(x-1)# #2/3-2=-(5x-3)/(x-1)# #-4/3=-(5x-3)/(x-1)# #4/3=(5x-3)/(x-1)# #4/3(x-1)=5x-3# #4(x-1)=3(5x-3)# #4x-4=15x-9# #4x-15x=-9+4# #-11x=-5# #x=5/11#. Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1319 views around the world You can reuse this answer Creative Commons License