How do you find the slope that is perpendicular to the line #3x-2y=7#?

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Answer 1 · 2016-06-20T16:55:32

#m= -2/3#

First, write the equation in standard form, #y = mx + c#

#2y = 3x - 7#

#y = 3/2x - 3½#

The gradient of this line is #3/2#

The slope perpendicular to this is #-2/3#

The one is the negative reciprocal of the other.

#m_1 xx m_2 = -1#

#3/2 xx -2/3 = -1#

Answer 2 · 2016-06-20T16:55:37

Reqd. slope #=-2/3.#

We write the given eqn. of line as #3x-7=2y,# or, #y=3/2x-7/2#, giving its slope#=3/2.#

Hence, the slope of a line perp. to this is #-1/(3/2)=-2/3.#