Question

How do you write an equation for a circle with Centre at (-1,- 6) with radius 1/3?

Answer 1

`(x+1)^2+(y+6)^2=1/9`

Explanation:

The standard form of the equation of a circle is.

`color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))`
where (a ,b) are the coordinates of the centre and r, the radius.

here a = -1 , b = -6 and r `=1/3`

Substitute these values into the standard equation.

`rArr(x+1)^2+(y+6)^2=1/9" is the equation of the circle"`