Question

How do you differentiate `y= (8/x^3)((x + x^7)/5)`?

Answer 1

`(dy)/(dx)=-16/(5x^3)+32/5x^3`

Explanation:

The function `y=(8/x^3)((x+x^7)/5)`

= `8/5xx((x+x^7)/x^3)`

= `8/5xx(x/x^3+x^7/x^3)`

= `8/5xx(1/x^2+x^4)`

Hence `(dy)/(dx)=8/5xx((-2)/x^3+4x^3)`

or `(dy)/(dx)=-16/(5x^3)+32/5x^3`