Question

How do you solve `4(u+1)^2=18`?

Answer 1

`u= -1+-(3sqrt(2))/2`

Explanation:

`4(u+1)^2=18larr` Divide both sides by 4

`(u+1)^2=18/4 larr` Square root both sides

`u+1=+-sqrt(18/4)larr` Subtract 1 from both sides

`u=+-sqrt(18/4)-1larr` simplify the square root

`u=-1+-sqrt(2xx3^2)/sqrt(2^2)larr`

`u= -1+-(3sqrt(2))/2`