Question

How do you write the equation of the circle with center point (2,4) and passing through point (4,-1)?

Answer 1

`(x-2)^2+(y-4)^2=29`

Explanation:

The radius of the circle is
`color(white)("XXX")r=sqrt((2-4)^2+(-1-4)^2)=sqrt(29)`

The general formula for a circle with center `(a,b)` and radius `r` is
`color(white)("XXX")(x-a)^2+(y-b)^2=r^2`

In this case
`color(white)("XXX")(x-2)^2+(y-4)^2=29`