How this reaction (during qualitative analysis) is possible: #Zn^(2+)# + NaOH ------> #Zn(OH)2# + #Na^(2+)# if Zinc is below Sodium in the reactivity series?
In qualitative analysis zinc's reaction with Sodium hydroxide produces #Zn(OH)2# which is soluble in excess of NaOH. I mean how is this possible: Zn displacing more reactive metal Na.
In qualitative analysis zinc's reaction with Sodium hydroxide produces
1 Answer
Jun 24, 2016
?
Explanation:
you are confused. Na is the more reactive, while Na+ (and not Na2+, that doesn't exist) is a spectator ion. Zn2+ is an amphoteric ion. The doer with zinc is the hydroxyl ion
