In a #DeltaABC#, #b=10m#, #c=21m# and #/_A=58^o#. What is the area of the triangle?

Question

(a) #105# #m^2#
(b) #55.64# #m^2#
(c) #82.02# #m^2#
(d) #89.05# #m^2#

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Answer 1 · 2016-06-26T17:18:38

(d) #89.05#.

As #b=10m#, #c=21m# and #/_A=58^o#

Area of the triangle is given by

#1/2xxbxxcxxsinA#

= #1/2xx10xx21xxsin58^o#

= #1/2xx10xx21xx0.84805#

= #5xx21xx0.848=89.05# #m^2#

Hence answer is (d) #89.05#.