What is the standard form of $y= (x - 8) (x+6)$ ?

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Answer 1 · 2016-06-27T06:50:58

$y=x^2-2x-48$

It is a quadratic function and standard form of quadratic function is

$y=ax^2+bx+c$

To convert, let us multiply the RHS as follows:

$y=(x-8)(x+6)$

= $x(x+6)-8(x+6)$

= $x^2+6x-8x-48$

= $x^2-2x-48$

What is the standard form of y= (x - 8) (x+6) y= (x - 8) (x+6) ?