Question

How do you find the value of `sin ((2pi)/3)`?

Answer 1

`sin((2pi)/3)=sqrt3/2`

Explanation:

As `sin2A=2sinAcosA`

`sin((2pi)/3)=2sin(pi/3)cos(pi/3)`

= `2xxsqrt3/2xx1/2`

= `1cancel(2)xxsqrt3/2xx1/(1cancel(2))`

= `sqrt3/2`