Question

How do you solve `Sin (4theta) - Sin(6theta) = 0`?

Answer 1

`theta = (npi)/5, n=0, +-1, +-2, +-3, ...`

Explanation:

`sin 4theta-sin 6theta = -2 sin theta sin 5theta=0`

So sin theta = 0#, giving

`theta =npi, n=0, +-1, +-2, +-3, ..` and

`sin 5theta=0` giving `theta=npi)`, and so,

`theta=(npi )/5, n=0, +-1, +-2, +-3, ..`

The second set includes the first, as a subset.