How do you expand #log_2 (16/sqrt(x-1))#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Noah G Jun 28, 2016 #=log_2(16) - log_2(sqrt(x - 1))# #=4 - log_2(x - 1)^(1/2)# #=4 - 1/2log_2(x - 1)# Hopefully this helps! Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 1345 views around the world You can reuse this answer Creative Commons License