How do you change the expression #5^(1/2)# to radical form?

1 Answer
Jun 29, 2016

#5^(1/2)=color(blue)(sqrt(5))#

Explanation:

This is basically a definition:
#color(white)("XXX")b^(1/a)=root(a)(b)#

To see why this is a reasonable definition
consider that in general
#color(white)("XXX")b^(2k)=b^k*b^k#

In the case of #5^(1/2)#
#color(white)("XXX")5=5^1=(5^(1/2))*(5^(1/2))#
that is
#color(white)("XXX")5^(1/2)# must be a value which when multiplied by itself is equal to #5#
and since #sqrt(5)*sqrt(5)=5#, the primary solution to this is
#color(white)("XXX")5^(1/2)=sqrt(5)#