How do you solve # 7(-3y + 2) = 8(3y - 2) #?

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Answer 1 · 2016-07-01T04:54:37

#7(-3y+2)=8(3y-2)#

First, distribute the seven and eight.

#-21y+14=24y-16#

Next, add #21y# to both sides.

#14=45y-16#

And then, add sixteen to both sides to isolate the #y#.

#30=45y#

Divide 30 by 45 to solve for #y#

#y=30/45#

Simplify! - Both are divisible by 5.

#y=6/9#

Both are divisible by 3.

#y=2/3#