How do you use the discriminant to determine the nature of the solutions given #y = x^2 + 25– 10x#?

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Answer 1 · 2016-07-02T15:40:54

The roots are real and identical because, discriminant #D=0#
The roots are #x_1=5/2# and #x_2=5/2#

The given equation is

#y=x^2-10x+25#

and #a=1# and #b=-10# and #c=25#

The discriminant

#D=sqrt(b^2-4ac)#

#D=sqrt((-10)^2-4(1)(25))#

#D=sqrt(100-100)#

#D=0#

God bless....I hope the explanation is useful.