Question

What is the polar form of `( 17,15 )`?

Answer 1

`(sqrt514, 41.423665625^@)`

Explanation:

Given `x=17` and `y=15`

`r=sqrt(x^2+y^2)=sqrt(17^2+15^2)=sqrt(289+225)=sqrt(514)`

`theta=tan^-1 (y/x)=tan^-1 (15/17)=41.423665625^@`

God bless....I hope the explanation is useful.