Question

The gas inside of a container exerts `24 Pa` of pressure and is at a temperature of `85 ^o K`. If the temperature of the gas changes to `17 ^oK` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

`P_l=4.8" "Pa`

Explanation:

`P_i:"initial pressure of gas ;"v_i=24" "Pa`

`P_l:"last pressure of gas ;"v_l=?`

`T_i:"initial temperature of gas ;"T_i=85" "K^ o`

`T_l:"last temperature of gas ;"T_l=17" "K^ o`

`P_i/T_i=P_l/T_l`

`24/85=P_l/17`

`P_l=(24*17)/85`

`P_l=4.8" "Pa`