How do you find the domain and range of f(x)=1/(x+3)?

1 Answer
Jul 4, 2016

D_f =RR-{-3}.
R_f=RR-{0}.

Explanation:

Remember that Division by 0 is not allowed, so, in our f(x), x+3!=0. i.e., x!=-3.

So, Domain of f, denoted by D_f, is RR-{-3}.

Also, note that, AA x in D_f, f(x)!=0, if so, then 1/(x+3)=0 rArr 1=0, an impossibility. That gives us the Range of f=R_f=RR-{0}.